32w^2-16w+2=0

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Solution for 32w^2-16w+2=0 equation: 



32w^2-16w+2=0

a = 32; b = -16; c = +2;
Δ = b2-4ac
Δ = -162-4·32·2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{16}{64}=1/4$

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